0=-2x^2+2000x

Solution for 0=-2x^2+2000x equation:

0=-2x^2+2000x

We move all terms to the left:

0-(-2x^2+2000x)=0

We add all the numbers together, and all the variables

-(-2x^2+2000x)=0

We get rid of parentheses

2x^2-2000x=0

a = 2; b = -2000; c = 0;
Δ = b2-4ac
Δ = -20002-4·2·0
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4000000}=2000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2000)-2000}{2*2}=\frac{0}{4}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2000)+2000}{2*2}=\frac{4000}{4}
=1000
$